Linearization Steps - Query Related to Exam Solution Method

[UdoWeber]

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Lin(C) = {C, Lin(A) >> Lin(B)}

!=

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Lin(C) = {C, Lin(A) >> Lin(B) >> Lin(AnyRef)}

The second line is probably not what you want, since AnyRef is usually not mixed-in like other classes. Because class C would have to look like this:

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class C extends AnyRef with B with A

However, since it does not look like this and probably no class will, the first line is what you want to do.

Yes, I think so too.
Thanks Udo