Yes, I think so too.Jan.K hat geschrieben: ↑15. Jul 2018 10:02The second line is probably not what you want, since AnyRef is usually not mixed-in like other classes. Because class C would have to look like this:UdoWeber hat geschrieben: ↑15. Jul 2018 00:20!=Code: Alles auswählen
Lin(C) = {C, Lin(A) >> Lin(B)}
Code: Alles auswählen
Lin(C) = {C, Lin(A) >> Lin(B) >> Lin(AnyRef)}
However, since it does not look like this and probably no class will, the first line is what you want to do.Code: Alles auswählen
class C extends AnyRef with B with A
Thanks Udo