Exercise # 2 - Task # 1 - DSL Syntax confusion

[AizazZaidee]

Hi,
following is mentioned in the exercise question...

In this exercise, you have
to specify them in the linearization, but you can insert them together in one step.
Provide the linearization, including all intermediate steps of the algorithm, even for the resolution of the » operator,
for trait D, and the classes E, F, G.

1) What does "you can insert them together in one step"

Does it means that

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Lin("G", Lin("C")) ===
        Lin("G", LinResult("X", "X", "X")) 

can be replaced by

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Lin("G", LinResult("X", "X", "X"))

2) resolution of the » operator ... How do I provide linearization for this operator?

for example I would do something like this

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class A { print("A") }
trait H { print("H") }
trait S extends H { print("S") }
trait R { print("R ") }
trait T extends R with H { print("T") }
class B extends A with T with S { print("B") }

new B  // A R H T S B

// lin(B) = B >> lin(S) >> lin(T) >> lin(A)
//        = B >> (S >> H) >> (T >> H >> R) >> A
//        = B >> S >> T >> H >> R >> A 

but I am still not clear what do you mean by linearization of >> operator and how to do it in code with you provided example!

The problem is not what to do it but since there is no documentation or example how to use those methods provided in DSL, I have no idea as how to do it. Please provide example usage of your methods as there are also no test cases so how do I know if I have done something right or wrong?

Thanks,

[pmueller]

1) What does "you can insert them together in one step"

This just concerns Any and AnyRef.

2) resolution of the » operator ... How do I provide linearization for this operator?

Maybe you could have a look at the other thread, which contains examples from another student.

Best,
Patrick

[labataschö]

Maybe you could have a look at the other thread, which contains examples from another student.

That would be this thread: viewtopic.php?f=234&t=37977

When you encounter something like this:

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Lin("Foo", >>(LinResult("Bar"), >>(LinResult("Foo", "Bar"), LinResult("Bar", "Foo"))))

you need to first compute the inner linearization result, that is the result of

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>>(LinResult("Foo", "Bar"), LinResult("Bar", "Foo"))

And as the task description says, you need to do it step by step. Next step in the computation of the inner linearization would hence be (according to the second rule for >>):

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>>(LinResult("Bar"), LinResult("Bar", "Foo"))

[labataschö]

Just saw that there's also another thread on this: viewtopic.php?f=234&t=37997
Maybe both help you to understand what to do.

[AizazZaidee]

Thanks everyone for your answers but I cannot wrap my head around your API... it's really a simple concept I don't know what's the point of making it a rocket science. As I have given example above it's pretty simple.

Thanks,